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ContentTheory of Equation
Theory of EquationDeterminants554 Definitions: The determinantπ1π2π1π2is equivalent to π1π2βπ2π1, and is called a determinant of the second order. A determinant of the third order is π1π2π3π1π2π3π1π2π3β‘π1(π2π3βπ3π2)+π2(π3π1βπ1π3)+π3(π1π2βπ2π1) Another notation is βΒ±π1π2π3, or simply (π1π2π3). The letters are named constituents, and the terms are called elements. The determinant is composed of all the elements obtained by permutations of the suffixes 1, 2, 3. The coefficients of the constituents are determinants of the next lower order, and are termed minors of the original determinant. Thus, the first determinant above is the minor of π3 in the second determinant. It is denoted by πΆ3. So the minor of π1 is denoted by π΄1, and so on. 555 A determinant of the πth order may be written in either of the forms below π1π2β―ππβ―πππ1π2β―ππβ―ππβ―β―β―β―β―β―π1π2β―ππβ―ππor π11π12β―π1πβ―π1ππ21π22β―π2πβ―π2πβ―β―β―β―β―β―ππ1ππ2β―πππβ―πππIn the latter, or double suffix notation, the first suffix indicates the row, and the second the column. The former notation will be adopted in these pages. A Composite determinant is one in which the number of columns exceeds the number of rows, and it is written as in the annexed example. π1π2π3π1π2π3Its value is the sum of all the determinants obtaied by taking a number of rows in every possible way. A Simple determinant has single terms for its constituents. A Compound determinant has more than one term in some or all of its constituents. See (570) for an example. For the definitions of Symmetrical, Reciprocal, artial, and Complementary determinants; see (574), (575), and (576). General Theory556 The number of constituents is π2. The number of elements in the complete determinant is|n. 557 The first or leading element is π1π2π3β―ππ. Any element may be derived from the first by permutation of the suffixes. The sign of an element is + or β according as it has been obtained from the diagonal element by an even or odd number of permutations of the suffixes. Hence the following rule for determining the sign of an element. RuleTake the suffixes in order, and put them back to their places in the first element. Let π be the whole number of places passed over; then (β1)π will give the sign required.ExampleTo find the sign of the element π4π3π5π1π2 of the determinant (π1π2π3π4π5). π4π3π5π1π2
Move the suffix 1, three places β―14352
Move the suffix 2, three places β―12435
Move the suffix 3, one place β―12345
In all, seven places; therefore (β1)7=β1 gives the sign required.
558
If two suffixes in any element be transposed, the sign of the element is changed.Half of the elements are plus, and half are minus. 559 The elements are not altered by changing the rows into columns. If two rows or columns are transposed, the sign of the determinant is changed. Because each element changes its sign. If two rows or columns are identical, the determinant vanishes. 560 If all the constituents but one in a row or column vanish, the determinant becomes the product of that constituent and a determinant of the next lower order. 561 A cyclical interchange is effected by πβ1 successive transpositions of adjacent rows or columns, until the top row has been brought to the bottom, or the left column to the right side. Hence A cyclical interchange changes the sign of a determinant of an even order only. The πth row may be brought to the top by πβ1 cyclical interchanges. 562 If each constituent in a row or column be multiplied by the same factor, the determinant becomes multiplied by it. If each constituent of a row or column is the sum of π terms, the compound determinant becomes the sum of π simple determinants of the same order. Also, if every constituent of the determinant consists of π terms, the compound determinant is resolvable into the sum of π2 simple determinants. 563 To express the minor of the πth row and πth column as a determinant of the πβ1th order. Put all the constituents in the πth row and πth column equal to 0, and then make πβ1 cyclical interchanges in the rows and πβ1 in the columns, and multiply by (β1)(π+π)(πβ1). [β΅ =(β1)(πβ1+πβ1)(πβ1). 564 To express a determinant as a determinant of a higher order. continue the diagonal with constituents of "ones", and fill up with zeros on one side, and with any quantities whatever (πΌ, π½, πΎ, β―) on the other. 10000 πΌ1000 π½ππβπ πΎπβππ πΏππππ565 The sum of the products of each constituent of a column by the corresponding minor in another given column is zero. And the same is true if we read 'row' instead of 'column'. Thus, referring to the determinant in (555), Taking the πth and πth columns, πππ΄π+πππ΅π+β―+πππΏπ=0 Taking the π and π rows, π1πΆ1+π2πΆ2+β―+πnπΆn=0 For in each case we have a determinant with two columns identical. 566 In any row or column the sum of the products of each constituent by its minor is the determinant itself. That is, Taking the πth column, πππ΄π+πππ΅π+β―+πππΏπ=β Or taking the π row, π1πΆ1+π2πΆ2+β―+πnπΆn=β 567 The last equation may be expressed by βπππΆπ=β. Also, if (πππΆπ) express the determinant ππππππππ; then β(ππππ) will represent the sum of all the determinants of the second order which can be formed by taking any two columns out of the π and π rows. The minor of (ππ, ππ) may be written (π΄π, πΆπ), and signifies the determinant obtained by suppressing the two rows and two columns of ππ and ππ. Thus β=β(ππ, ππ)(π΄π, πΆπ). And a similar notation when three or more rows and columns are selected. 568 Analysis of a DeterminantRuleTo resolve into its elements a determinant of the πth order. Express it as the sum of π determinants of the (πβ1)th order by (560), and repeat the process with each of the new determinants.Exampleπ1π2π3π4 π1π2π3π4 π1π2π3π4 π1π2π3π4=π1 π2π3π4 π2π3π4 π2π3π4βπ2 π3π4π1 π3π4π1 π3π4π1+π3 π4π1π2 π4π1π2 π4π1π2βπ4 π1π2π3 π1π2π3 π1π2π3Again, π1π2π3 π1π2π3 π1π2π3=π1 π2π3 π2π3+π2 π3π1 π3π1+π3 π1π2 π1π2and so on. In the first series the derminants have alternately plus and minus signs, by the rule for cyclical interchanges (561), the order being even. 569 Synthesis of a determinantThe process is facilitated by making us of two evident rules. Those constituents which belong to the row and column of a given constituent π, will be designated "π's constituents". Also , two pairs of constituents such as ππ, ππ and ππ, ππ, forming the corners of a rectangle, will be said to be "conjugate: to each other. Rule I. No constituent will be found in the same term with one of its own constituents. Rule II> The conjugates of any two constituents π and π will be common to π's and π's constituents.ExampleTo write the following terms in the form of a determinant: ππππ+ππππ+π2β2+1πππ+ππβπ+1πβπ+ππππβπβππβππππβππβ2β1πβπβπππ2βππβπβππππ The determinant will be of the fourth order; and since every term must conatin four constituents, and the constituent 1 is supplied to make up the number in some of the terms. select any term, as ππππ. for the leading diagonal.Now apply Rule I., π is not found with π, π, π, π, π, 0, β―1 π is not found with π, β, β, π, 1, 0, β―2 π is not found with π, π, π, π, 1, 0, β―3 π is not found with π, β, β, π, π, 0, β―4 Each constituent has 2(πβ1), that is, 6 constituents belonging to it, since π=4. Assuming, therefore, that the above letters are the constituents of π, π, π, and π, and that there are no more, we supply a sixth zero constituent in each case. Now apply Rulle II. The constituents common to π and π are π, π; to π and π are π, π; to π and π are π, 0; to π and π are 1, 0 to π and d are β, β, 0; to π and d are π, π, 0; The determinant may now be formed. The diagonal being ππππ; place π, π, the conjugates of π and π, either as in the diagram or transposed. Then π, and π, the conjugates of π and π, may be written. 1 and 0, the conjugates of π and π, must be placed as indicated, because 1 is one of π's constituents, since it is not found in any term with π, and must therefore be in the second row. Similarly the places of π and 0, and π, and π, are assigned. In the case of π and d we have β, β, 0 from which to choose the two conjugates, but we see that 0 is not one of them because that would assign two zero constituents to π, whereas π has but one, which is already placed. By similar reasoning the ambiguity in selecting the conjugates π, π is removed. ππππ ππ1β π0ππ 0βπdThe foregoing method is rigid in the case of a complete determinant having different constituents. It becomes uncertain when the zero constituents increase in number, and when several constituents are identical. But even then, in the majority of cases, it will soon afford a clue to the required arrangement. Sources and Referenceshttps://archive.org/details/synopsis-of-elementary-results-in-pure-and-applied-mathematics-pdfdriveΒ©sideway ID: 210800022 Last Updated: 8/22/2021 Revision: 0 Ref: References
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