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ContentAlgebra
AlgebraMultinomial TheoremThe general term in the expansion of (𝑎+𝑏𝑥+𝑐𝑥2+⋯)𝑛 is𝑛(𝑛−1)(𝑛−2)⋯(𝑝+1)𝑞!𝑟!𝑠!⋯𝑎𝑝𝑏𝑞𝑐𝑟𝑑𝑠⋯𝑥𝑞+2𝑟+3𝑠+⋯, where 𝑝+𝑞+𝑟+𝑠+⋯=⋯, and the number of terms 𝑝, 𝑞, 𝑟, ⋯ corresponds to the number of terms in the given multinomial. 𝑝 is integral, fractional, or negative, according as 𝑛 is one or the other. If 𝑛 be an integer, may be written 𝑛𝑝!𝑞!𝑟!𝑠!𝑎𝑝𝑏𝑞𝑐𝑟𝑑𝑠⋯𝑥𝑞+2𝑟+3𝑠 Deduced from the Binomial Theorem. ExamplesTo write the coefficient of 𝑎3𝑏𝑐5 in the expansion of (𝑎+𝑏+𝑐+𝑑)10. Here put 𝑛=10, 𝑥=1, 𝑝=3, 𝑞=1, 𝑟=5, 𝑠=0. Result:10!3!5!=7⋅8⋅9⋅10 ExamplesTo obtain the coefficient of 𝑥8 in the expansion of (1−2𝑥+3𝑥2−4𝑥3)4. Here 𝑎=1, 𝑏=−2, 𝑐=3, 𝑑=−4, 𝑝+𝑞+𝑟+𝑠=4 𝑞+2𝑟+3𝑠=8 Possible values: 𝑝𝑞𝑟𝑠 1012 0202 0121 0040 The numbers 1, 0, 1, 2 are particular values of 𝑝, 𝑞, 𝑟, 𝑠 respectively, which satisfy the two equations given above. 0, 2, 0, 2 are another set of values which also satisfy those equations; and the four rows of numbers constitute all the solutions. In forming these rows always try the highest possible numbers on the right first. Now substitute each set of values of 𝑝, 𝑞, 𝑟, 𝑠 in the formula successively,4!2!11(−2)031(−4)2=576 4!2!2!10(−2)230(−4)2=384 4!2!10(−2)132(−4)1=864 4!4!10(−2)034(−4)0=84 Result 1905 ExamplesRequired the coefficient of 𝑥4 in (1+2𝑥−4𝑥2−2𝑥3)−12Here 𝑎=1, 𝑏=2, 𝑐=−4, 𝑑=−2, 𝑛=− 12; and the two equations are 𝑝+𝑞+𝑟+𝑠=− 12𝑞+2𝑟+3𝑠=4 Possible values: 𝑝𝑞𝑟𝑠
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Employing the formula, the remainder of the work stands as follows:
Result: 2238 ExamplesThe number of terms in the expansion of the multinomial (𝑎+𝑏+𝑐+ to 𝑛 terms)𝑟 is the same as the number of homogeneous products of 𝑛 things of 𝑟 dimensions.ExamplesThe greatest coefficient in the expansion of (𝑎+𝑏+𝑐+ to 𝑚 terms)𝑛, 𝑛 being an integer is𝑛!(𝑞!)𝑚(𝑞+1)(𝑘), where 𝑞𝑚+𝑘=𝑛Proof: By making the denominator in previous equation as small as possible. The notation is same as in Permutations, Combinations. Sources and Referenceshttps://archive.org/details/synopsis-of-elementary-results-in-pure-and-applied-mathematics-pdfdrive©sideway ID: 210600011 Last Updated: 6/11/2021 Revision: 0 Ref: References
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