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ContentTheory of Equation
Theory of EquationCommensurable Roots502 To find the commensurable roots of an equation. First transform it by putting π₯=π¦πinto an equation of the form π₯π+π1π₯πβ1+π2π₯πβ2+β―+ππ=0 having π0=1, and the remaining coefficients integers. 431 503 This equation cannot have a rational fractional root, and the integral roots may be found by Newton's method of Divisors (459). These roots, divided each by π, will furnish the commensurable roots of the original equation. 504 Example: To find the commensurable roots of the equation 81π₯5β207π₯4β9π₯3+89π₯2+2π₯β8=0 Dividing by 81, and proceeding as in (431), we find the requisite substitution to be π₯= π¦9The transformed equation is π¦5β23π¦4β9π¦3+801π¦2+162π¦β5832=0 The roots all lie between 24 and β34, by (451). The method of divisors gives the integral roots 6, β4, and 3. Therefore, dividing each by 9, we find the commensurable roots of the original equation to be 23, β 49, and 13, 505 To obtain the remaining roots; diminish the transformed equation by the roots 6, β4, and 3, in the following manner (see 427):
1β23β9+801+162β5832
6 6β102+666+810β5832
1β17β111+135+972
-4 β4+84+108β972
1β21β27+243
-3 3β54β243
1β18β31
The depressed equation is therefore
π¦2β18π¦β81=0
The roots of which are 9(1+) and 9(1β ); and, consequently, the incommensurable roots of the proposed equation are 1+ and 1β . Sources and Referenceshttps://archive.org/details/synopsis-of-elementary-results-in-pure-and-applied-mathematics-pdfdriveΒ©sideway ID: 210800014 Last Updated: 8/14/2021 Revision: 0 Ref: References
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