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AlgebraHighest Common FactorRule: To find the highest common factor of two expressions: Divide the one which is of the highest dimension by the other, rejecting first any factor of either expression which is not also a factor of the other. Operate in the same manner upon the remainder and the divisor, and continue the process until there is no remainder. The last divisor will be the highest common factor required.Exampleto find the H.C.F. of 3𝑥5−10𝑥3+15𝑥+8 and 𝑥5−2𝑥4−6𝑥3−4𝑥2+13𝑥+6.𝑥 | 5 4 3 2 1 0 | 5 4 3 2 1 0 | - | ----------------- | ---------------- | -- | 1− 2− 6+ 4+13+ 6 | 3+0−10+ 0+15+ 8 | 3 | 3× | −3+6−18−12−39−18 | | ----------------- | ---------------- | 𝑥 | 3− 6−18+12+39+18 | 2)6+ 8−12−24−10 | | −3− 4+ 6+12+ 5 | 3+ 4− 6−12− 5 | | ----------------- | | | 2)−10−12+24+44+18 | | | − 5− 6+12+22+ 9 | | | 3 | | | ----------------- | | 5 | −15−18+36+66+27 | | | +15+20−30−60−25 | | | ----------------- | ---------------- | | 2) 2+ 6+ 6+ 2 | 3+ 4− 6−12− 5 | 3𝑥 | 1+ 3+ 3+ 1 | −3− 9− 9− 3 | | | ---------------- | | | − 5−15−15− 5 | −5 | | + 5+15+15+ 5 | | | ---------------- | EvolutionOtherwise: To form the H.C.F. of two or more algebraical expressions: Separate the expressions into their simplest factors. The H.C.F. will be the product of the factors common to all the expressions, taken in the lowest powers that occur.Lowest Common MultipleThe L.C.M. of two quantities is equal to their product divided by the H.C.F. Otherwsise.: To form the L.C.M. of two or more algebraical expressions: Separate them into their simplest factors. The L.C.M. will be the product of all the factors that occur, taken in the highest powers that occur.ExampleThe H.C.F. of 𝑎2(𝑏−𝑥)5𝑐7𝑑 and 𝑎3(𝑏−𝑥)2𝑐4𝑒 is 𝑎2(𝑏−𝑥)2𝑐4; the L.C.M. is 𝑎3(𝑏−𝑥)5𝑐7𝑑𝑒EvolutionSquare RootTo extract the Square Root of 𝑎2−3𝑎√𝑎2− 3√𝑎2+ 41𝑎16+1 16𝑎2−24𝑎 32+41𝑎−24𝑎 12+1616 Detaching the coefficients, the work is as follows: 𝑎 | 2⇒root:321120 1120 ----- | -------------- | 16−24+41−24+16 ( 4-3+4 4 | −16 | -------------- 2×4 | −24+41 8-3 | 24− 9 | -------------- 8-2×3 | 32−24+16 8-6+4 | −32+24−16 34√𝑎+1 Cube RootTo extract the Cube Root of 8𝑥6−36𝑥5√𝑦+66𝑥4𝑦−63𝑥3𝑦√𝑦+33𝑥2𝑦2−9𝑥𝑦2√𝑦+𝑦3 The terms here contain the successive powers of 𝑥 and √𝑦; therefore, detaching the coefficients, the work will be as follow:4 3 |2 1 0|4 3 2 1 0| 6 5 4 3 2 1 0|2 1 0 ---|-----|---------|------------------ | | | 8−36+66−63+33−9+1(2−3+1 22|3×2|3×22|−8⇒2 | | |------------------ | | | −36+66−63+33−9+1 3×22|3×2−3|3×22−3×2(3)+(−3)2| +36⇒−3 | | |------------------ | | | +66−63+33−9+1 | |0−18+9| −54+27 | | |------------------ | | | +12−36+33−9+1 3×22|3×2(1)−3×3(1)+12|0−2x3×2(3)+3×(−3)2| −12⇒1 | | |------------------ | | | −36+33−9+1 | |0−36+27| +36−27 |6−9+1| | −06+9−1⇒root:2𝑥2−3𝑥√𝑦+𝑦 The foregoing process is but a slight variation of Horner's rule for solving an equation of any degree Sources and Referenceshttps://archive.org/details/synopsis-of-elementary-results-in-pure-and-applied-mathematics-pdfdrive©sideway ID: 210500031 Last Updated: 5/31/2021 Revision: 0 Ref: References
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