Rules of Integration for Indefinite
Integral
Method of Partial Fractions for
Indefinite Integral
Integration by Partial Fractions
Rules of Integration for Indefinite
Integral
Method of Partial Fractions for
Indefinite Integral
where Φ(x) and φ(x) are rational, integral, algebraical functions of x
The integrand after denominator factorization is
Integration by Partial Fractions
The method of integration by partial fractions can be expressed as
The integral of polynomial Q(x) can be obtained by making use of the constant
multiple, sum of function properties of intergration and applying the
anti-differentiation of the derivative of polynomial. The integration of the four case of fraction factors after partial fractions are:
linear partial fraction
A/(ax+b)
This is the most common type of partial fraction, the integral of the linear
partial fraction can be
obtained by the quotient of standard functions rule of indefinite integral,
Therefore the integral of linear partial fraction can be determined by:
repeated linear partial fraction A/(ax+b)k
This is the most simple type of partial fraction.The integral of the repeated linear
partial fraction can be
obtained by product of standard functions rule of indefinite integral.
Therefore the integral of repeated linear partial fraction can be determined by:
quadratic partial fractionr (Ax+B)/(ax2+bx+c)
For the quadratic partial fraction, there are some variant forms.
Standard quadratic partial fraction (Ax+B)/(ax2+bx+c).
If the numerator can be expressed as the derivative of the denumerator, imply
If the numerator can not be expressed as the derivative of the denumerator, imply
For the last integral, the quadratic factor can be resolved by completing the
square, imply
Since the quadratic factor is irreducible, 4ac-b2>0,
imply
Therefore the integral is
Quadratic partial fraction Ax/(ax2+bx+c).
Same as a.ii case where B=0, imply
Quadratic partial fraction B/(ax2+bx+c). Same as the
last integral in a.ii case where B=D, imply
Quadratic partial fraction with quadratic factor, (ax2+bx)
Quadratic
factor (ax2+bx) is same as (ax2+bx+c)
by letting c=0, the
integral can be obtained as in case a
Quadratic partial fraction with quadratic factor, (ax2+c)
Quadratic
factor (ax2+c) is same as (ax2+bx+c)
by letting b=0, the
integral can be obtained as in case a. But no complete the square is needed
since the factor can be directly transformed into needed format., imply
repeated
quadratic factor (Ax+B)/(ax2+bx+c)k
The
proceduce of determine the integral is same as case 3 except for the determining
of the integral with power after decomposing the original integral into two
integrals. Imply
The
first integral can be obtained by simple substitution. Imply
The second integral can be obtained by simple substitution. Imply
The
second integral can further be expanded using the formule in integration by part
as:
The
theta angle can be transformed back to x through trigonometry, imply: